Base | Representation |
---|---|
bin | 1010011010101100001110… |
… | …0010110100001101101111 |
3 | 1111112221220111120001022221 |
4 | 2212223003202310031233 |
5 | 3000124100323320043 |
6 | 40205423530420211 |
7 | 2261333313233521 |
oct | 246530342641557 |
9 | 44487814501287 |
10 | 11453663495023 |
11 | 37165204a03a2 |
12 | 134b968891667 |
13 | 6510ca7b3c39 |
14 | 2b8508825a11 |
15 | 14ce0939c8ed |
hex | a6ac38b436f |
11453663495023 has 2 divisors, whose sum is σ = 11453663495024. Its totient is φ = 11453663495022.
The previous prime is 11453663494993. The next prime is 11453663495059. The reversal of 11453663495023 is 32059436635411.
It is a weak prime.
It is an emirp because it is prime and its reverse (32059436635411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11453663495023 - 217 = 11453663363951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11453663295023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5726831747511 + 5726831747512.
It is an arithmetic number, because the mean of its divisors is an integer number (5726831747512).
Almost surely, 211453663495023 is an apocalyptic number.
11453663495023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11453663495023 is an equidigital number, since it uses as much as digits as its factorization.
11453663495023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6998400, while the sum is 52.
The spelling of 11453663495023 in words is "eleven trillion, four hundred fifty-three billion, six hundred sixty-three million, four hundred ninety-five thousand, twenty-three".
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