Base | Representation |
---|---|
bin | 1010011010101101100110… |
… | …1000000100111110000111 |
3 | 1111112222212022200021202012 |
4 | 2212223121220010332013 |
5 | 3000130330144120002 |
6 | 40205524403204435 |
7 | 2261345432240564 |
oct | 246533150047607 |
9 | 44488768607665 |
10 | 11454033973127 |
11 | 37166a0632049 |
12 | 134ba5097671b |
13 | 65115948a055 |
14 | 2b8541b0386b |
15 | 14ce2bb7dd52 |
hex | a6ad9a04f87 |
11454033973127 has 2 divisors, whose sum is σ = 11454033973128. Its totient is φ = 11454033973126.
The previous prime is 11454033973103. The next prime is 11454033973159. The reversal of 11454033973127 is 72137933045411.
11454033973127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (72137933045411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11454033973127 - 230 = 11452960231303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11454033976127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5727016986563 + 5727016986564.
It is an arithmetic number, because the mean of its divisors is an integer number (5727016986564).
Almost surely, 211454033973127 is an apocalyptic number.
11454033973127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11454033973127 is an equidigital number, since it uses as much as digits as its factorization.
11454033973127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1905120, while the sum is 50.
The spelling of 11454033973127 in words is "eleven trillion, four hundred fifty-four billion, thirty-three million, nine hundred seventy-three thousand, one hundred twenty-seven".
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