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114542111250041 is a prime number
BaseRepresentation
bin11010000010110011101001…
…110110100101011001111001
3120000120010012200012100101012
4122002303221312211121321
5110003124220440000131
61043335530335203305
733061252203234146
oct3202635166453171
9500503180170335
10114542111250041
113355104476a742
1210a1b041376535
134bbb3757c6897
14203dc212093cd
15d3978332352b
hex682ce9da5679

114542111250041 has 2 divisors, whose sum is σ = 114542111250042. Its totient is φ = 114542111250040.

The previous prime is 114542111250037. The next prime is 114542111250113. The reversal of 114542111250041 is 140052111245411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114540509569600 + 1601680441 = 10702360^2 + 40021^2 .

It is an emirp because it is prime and its reverse (140052111245411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114542111250041 - 22 = 114542111250037 is a prime.

It is not a weakly prime, because it can be changed into another prime (114542111250011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271055625020 + 57271055625021.

It is an arithmetic number, because the mean of its divisors is an integer number (57271055625021).

Almost surely, 2114542111250041 is an apocalyptic number.

It is an amenable number.

114542111250041 is a deficient number, since it is larger than the sum of its proper divisors (1).

114542111250041 is an equidigital number, since it uses as much as digits as its factorization.

114542111250041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6400, while the sum is 32.

Adding to 114542111250041 its reverse (140052111245411), we get a palindrome (254594222495452).

The spelling of 114542111250041 in words is "one hundred fourteen trillion, five hundred forty-two billion, one hundred eleven million, two hundred fifty thousand, forty-one".