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114553031413 is a prime number
BaseRepresentation
bin110101010101111100…
…1001000101011110101
3101221200101201221022011
41222223321020223311
53334101034001123
6124342553004221
711163505462342
oct1525371105365
9357611657264
10114553031413
1144644221a97
121a24b6b3671
13aa57880832
145789b757c9
152ea6bade0d
hex1aabe48af5

114553031413 has 2 divisors, whose sum is σ = 114553031414. Its totient is φ = 114553031412.

The previous prime is 114553031339. The next prime is 114553031419. The reversal of 114553031413 is 314130355411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110611451889 + 3941579524 = 332583^2 + 62782^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114553031413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114553031419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57276515706 + 57276515707.

It is an arithmetic number, because the mean of its divisors is an integer number (57276515707).

Almost surely, 2114553031413 is an apocalyptic number.

It is an amenable number.

114553031413 is a deficient number, since it is larger than the sum of its proper divisors (1).

114553031413 is an equidigital number, since it uses as much as digits as its factorization.

114553031413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 114553031413 its reverse (314130355411), we get a palindrome (428683386824).

The spelling of 114553031413 in words is "one hundred fourteen billion, five hundred fifty-three million, thirty-one thousand, four hundred thirteen".