Base | Representation |
---|---|
bin | 1010011011001101001100… |
… | …0001001101011011000111 |
3 | 1111120210202020120022000112 |
4 | 2212303103001031123013 |
5 | 3000300211320233211 |
6 | 40213450015303235 |
7 | 2262065521244264 |
oct | 246632301153307 |
9 | 44523666508015 |
10 | 11462513055431 |
11 | 371a25187a089 |
12 | 135161851ab1b |
13 | 651bab040209 |
14 | 2b8b07c7a26b |
15 | 14d27625e88b |
hex | a6cd304d6c7 |
11462513055431 has 2 divisors, whose sum is σ = 11462513055432. Its totient is φ = 11462513055430.
The previous prime is 11462513055407. The next prime is 11462513055473. The reversal of 11462513055431 is 13455031526411.
11462513055431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11462513055431 is a prime.
It is a super-2 number, since 2×114625130554312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11462513055401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5731256527715 + 5731256527716.
It is an arithmetic number, because the mean of its divisors is an integer number (5731256527716).
Almost surely, 211462513055431 is an apocalyptic number.
11462513055431 is a deficient number, since it is larger than the sum of its proper divisors (1).
11462513055431 is an equidigital number, since it uses as much as digits as its factorization.
11462513055431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 41.
The spelling of 11462513055431 in words is "eleven trillion, four hundred sixty-two billion, five hundred thirteen million, fifty-five thousand, four hundred thirty-one".
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