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11462513055431 is a prime number
BaseRepresentation
bin1010011011001101001100…
…0001001101011011000111
31111120210202020120022000112
42212303103001031123013
53000300211320233211
640213450015303235
72262065521244264
oct246632301153307
944523666508015
1011462513055431
11371a25187a089
12135161851ab1b
13651bab040209
142b8b07c7a26b
1514d27625e88b
hexa6cd304d6c7

11462513055431 has 2 divisors, whose sum is σ = 11462513055432. Its totient is φ = 11462513055430.

The previous prime is 11462513055407. The next prime is 11462513055473. The reversal of 11462513055431 is 13455031526411.

11462513055431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11462513055431 is a prime.

It is a super-2 number, since 2×114625130554312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11462513055401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5731256527715 + 5731256527716.

It is an arithmetic number, because the mean of its divisors is an integer number (5731256527716).

Almost surely, 211462513055431 is an apocalyptic number.

11462513055431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11462513055431 is an equidigital number, since it uses as much as digits as its factorization.

11462513055431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 11462513055431 in words is "eleven trillion, four hundred sixty-two billion, five hundred thirteen million, fifty-five thousand, four hundred thirty-one".