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114716759569273 is a prime number
BaseRepresentation
bin11010000101010110010011…
…101101000011001101111001
3120001011211000012211012202001
4122011112103231003031321
5110014004410422204043
61043552052442541001
733110004146402341
oct3205262355031571
9501154005735661
10114716759569273
1133609117131954
1210a48a62807761
134c01989788304
14204846c359d21
15d3e0a5ca874d
hex685593b43379

114716759569273 has 2 divisors, whose sum is σ = 114716759569274. Its totient is φ = 114716759569272.

The previous prime is 114716759569271. The next prime is 114716759569309. The reversal of 114716759569273 is 372965957617411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68042899411344 + 46673860157929 = 8248812^2 + 6831827^2 .

It is a cyclic number.

It is not a de Polignac number, because 114716759569273 - 21 = 114716759569271 is a prime.

Together with 114716759569271, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 114716759569196 and 114716759569205.

It is not a weakly prime, because it can be changed into another prime (114716759569271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57358379784636 + 57358379784637.

It is an arithmetic number, because the mean of its divisors is an integer number (57358379784637).

Almost surely, 2114716759569273 is an apocalyptic number.

It is an amenable number.

114716759569273 is a deficient number, since it is larger than the sum of its proper divisors (1).

114716759569273 is an equidigital number, since it uses as much as digits as its factorization.

114716759569273 is an evil number, because the sum of its binary digits is even.

The product of its digits is 600112800, while the sum is 73.

The spelling of 114716759569273 in words is "one hundred fourteen trillion, seven hundred sixteen billion, seven hundred fifty-nine million, five hundred sixty-nine thousand, two hundred seventy-three".