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11472433 = 717253107
BaseRepresentation
bin101011110000…
…111000110001
3210120212012221
4223300320301
510414104213
61045521041
7166341220
oct53607061
923525187
1011472433
116526455
123a13181
1324b8b2b
141748cb7
15101938d
hexaf0e31

11472433 has 24 divisors (see below), whose sum is σ = 14323392. Its totient is φ = 8995584.

The previous prime is 11472431. The next prime is 11472437. The reversal of 11472433 is 33427411.

11472433 = 5022 + 5032 + ... + 5432.

11472433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11472433 - 21 = 11472431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11472398 and 11472407.

It is not an unprimeable number, because it can be changed into a prime (11472431) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 107166 + ... + 107272.

It is an arithmetic number, because the mean of its divisors is an integer number (596808).

Almost surely, 211472433 is an apocalyptic number.

It is an amenable number.

11472433 is a deficient number, since it is larger than the sum of its proper divisors (2850959).

11472433 is a wasteful number, since it uses less digits than its factorization.

11472433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201 (or 184 counting only the distinct ones).

The product of its digits is 2016, while the sum is 25.

The square root of 11472433 is about 3387.0980204299. The cubic root of 11472433 is about 225.5373690739.

Adding to 11472433 its reverse (33427411), we get a palindrome (44899844).

The spelling of 11472433 in words is "eleven million, four hundred seventy-two thousand, four hundred thirty-three".

Divisors: 1 7 17 53 107 119 289 371 749 901 1819 2023 5671 6307 12733 15317 30923 39697 96407 107219 216461 674849 1638919 11472433