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11474385806053 is a prime number
BaseRepresentation
bin1010011011111001011010…
…1100001010001011100101
31111121221101200020112001001
42212332112230022023211
53000444020231243203
640223132101433301
72262665656044502
oct246762654121345
944557350215031
1011474385806053
113724294718385
12135399070b831
13653050a10241
142b9512a124a9
1514d71d74691d
hexa6f96b0a2e5

11474385806053 has 2 divisors, whose sum is σ = 11474385806054. Its totient is φ = 11474385806052.

The previous prime is 11474385805931. The next prime is 11474385806057. The reversal of 11474385806053 is 35060858347411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11454691332484 + 19694473569 = 3384478^2 + 140337^2 .

It is a cyclic number.

It is not a de Polignac number, because 11474385806053 - 217 = 11474385674981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11474385805985 and 11474385806003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11474385806057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5737192903026 + 5737192903027.

It is an arithmetic number, because the mean of its divisors is an integer number (5737192903027).

Almost surely, 211474385806053 is an apocalyptic number.

It is an amenable number.

11474385806053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11474385806053 is an equidigital number, since it uses as much as digits as its factorization.

11474385806053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9676800, while the sum is 55.

The spelling of 11474385806053 in words is "eleven trillion, four hundred seventy-four billion, three hundred eighty-five million, eight hundred six thousand, fifty-three".