Base | Representation |
---|---|
bin | 1010011100001110011111… |
… | …0000010001100110001101 |
3 | 1111122110222210010022201001 |
4 | 2213003213300101212031 |
5 | 3001042110421304142 |
6 | 40225505152020301 |
7 | 2263256053544233 |
oct | 247034760214615 |
9 | 44573883108631 |
10 | 11480040806797 |
11 | 372672682a112 |
12 | 1354aaa531691 |
13 | 653742484024 |
14 | 2b98cba96953 |
15 | 14d94ee325b7 |
hex | a70e7c1198d |
11480040806797 has 2 divisors, whose sum is σ = 11480040806798. Its totient is φ = 11480040806796.
The previous prime is 11480040806791. The next prime is 11480040806873. The reversal of 11480040806797 is 79760804008411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9293114468521 + 2186926338276 = 3048461^2 + 1478826^2 .
It is a cyclic number.
It is not a de Polignac number, because 11480040806797 - 215 = 11480040774029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11480040806791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5740020403398 + 5740020403399.
It is an arithmetic number, because the mean of its divisors is an integer number (5740020403399).
Almost surely, 211480040806797 is an apocalyptic number.
It is an amenable number.
11480040806797 is a deficient number, since it is larger than the sum of its proper divisors (1).
11480040806797 is an equidigital number, since it uses as much as digits as its factorization.
11480040806797 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2709504, while the sum is 55.
The spelling of 11480040806797 in words is "eleven trillion, four hundred eighty billion, forty million, eight hundred six thousand, seven hundred ninety-seven".
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