Base | Representation |
---|---|
bin | 10000101101011101111… |
… | …111100101001001011111 |
3 | 11001210001022112120000212 |
4 | 100231131333211021133 |
5 | 122303241300410401 |
6 | 2235311554043035 |
7 | 145651524200516 |
oct | 20553577451137 |
9 | 4053038476025 |
10 | 1148333216351 |
11 | 4030071888a2 |
12 | 16667a57947b |
13 | 8439742b689 |
14 | 3d8186bb67d |
15 | 1ed0dd53dbb |
hex | 10b5dfe525f |
1148333216351 has 2 divisors, whose sum is σ = 1148333216352. Its totient is φ = 1148333216350.
The previous prime is 1148333216339. The next prime is 1148333216413. The reversal of 1148333216351 is 1536123338411.
It is a weak prime.
It is an emirp because it is prime and its reverse (1536123338411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1148333216351 - 230 = 1147259474527 is a prime.
It is a super-3 number, since 3×11483332163513 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1148333216299 and 1148333216308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1148333216851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574166608175 + 574166608176.
It is an arithmetic number, because the mean of its divisors is an integer number (574166608176).
Almost surely, 21148333216351 is an apocalyptic number.
1148333216351 is a deficient number, since it is larger than the sum of its proper divisors (1).
1148333216351 is an equidigital number, since it uses as much as digits as its factorization.
1148333216351 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 155520, while the sum is 41.
The spelling of 1148333216351 in words is "one trillion, one hundred forty-eight billion, three hundred thirty-three million, two hundred sixteen thousand, three hundred fifty-one".
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