Base | Representation |
---|---|
bin | 10000101101100000001… |
… | …011111001100011000110 |
3 | 11001210010212202100210211 |
4 | 100231200023321203012 |
5 | 122303330210000240 |
6 | 2235315350310034 |
7 | 145652451641626 |
oct | 20554013714306 |
9 | 4053125670724 |
10 | 1148370000070 |
11 | 403025a21a67 |
12 | 16668a95831a |
13 | 843a1c3a2a7 |
14 | 3d81d534886 |
15 | 1ed121bcbea |
hex | 10b602f98c6 |
1148370000070 has 8 divisors (see below), whose sum is σ = 2067066000144. Its totient is φ = 459348000024.
The previous prime is 1148369999989. The next prime is 1148370000077. The reversal of 1148370000070 is 700000738411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1148369999987 and 1148370000041.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1148370000077) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57418499994 + ... + 57418500013.
It is an arithmetic number, because the mean of its divisors is an integer number (258383250018).
Almost surely, 21148370000070 is an apocalyptic number.
1148370000070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1148370000070 is a deficient number, since it is larger than the sum of its proper divisors (918696000074).
1148370000070 is a wasteful number, since it uses less digits than its factorization.
1148370000070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114837000014.
The product of its (nonzero) digits is 4704, while the sum is 31.
Adding to 1148370000070 its reverse (700000738411), we get a palindrome (1848370738481).
The spelling of 1148370000070 in words is "one trillion, one hundred forty-eight billion, three hundred seventy million, seventy", and thus it is an aban number.
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