Base | Representation |
---|---|
bin | 100010010000010… |
… | …1101101100000101 |
3 | 2222002211220122112 |
4 | 1010200231230011 |
5 | 4323223121222 |
6 | 310020110405 |
7 | 40324651325 |
oct | 10440555405 |
9 | 2862756575 |
10 | 1149426437 |
11 | 53a904105 |
12 | 280b35405 |
13 | 154197cb3 |
14 | ac927285 |
15 | 6ad9abe2 |
hex | 4482db05 |
1149426437 has 2 divisors, whose sum is σ = 1149426438. Its totient is φ = 1149426436.
The previous prime is 1149426427. The next prime is 1149426461. The reversal of 1149426437 is 7346249411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1028228356 + 121198081 = 32066^2 + 11009^2 .
It is a cyclic number.
It is not a de Polignac number, because 1149426437 - 226 = 1082317573 is a prime.
It is a super-2 number, since 2×11494264372 = 2642362268149029938, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1149426394 and 1149426403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1149426427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574713218 + 574713219.
It is an arithmetic number, because the mean of its divisors is an integer number (574713219).
Almost surely, 21149426437 is an apocalyptic number.
It is an amenable number.
1149426437 is a deficient number, since it is larger than the sum of its proper divisors (1).
1149426437 is an equidigital number, since it uses as much as digits as its factorization.
1149426437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 145152, while the sum is 41.
The square root of 1149426437 is about 33903.1921358447. The cubic root of 1149426437 is about 1047.5153456664.
The spelling of 1149426437 in words is "one billion, one hundred forty-nine million, four hundred twenty-six thousand, four hundred thirty-seven".
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