Base | Representation |
---|---|
bin | 10101011010011011… |
… | …11010000000001101 |
3 | 1002200011211021000111 |
4 | 22231031322000031 |
5 | 142020441212123 |
6 | 5140424000021 |
7 | 554611466656 |
oct | 125515720015 |
9 | 32604737014 |
10 | 11496038413 |
11 | 496a2398a2 |
12 | 228a000011 |
13 | 11129234c2 |
14 | 7b0b1452d |
15 | 4743c390d |
hex | 2ad37a00d |
11496038413 has 2 divisors, whose sum is σ = 11496038414. Its totient is φ = 11496038412.
The previous prime is 11496038399. The next prime is 11496038423. The reversal of 11496038413 is 31483069411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6440544009 + 5055494404 = 80253^2 + 71102^2 .
It is an emirp because it is prime and its reverse (31483069411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11496038413 - 29 = 11496037901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11496038423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5748019206 + 5748019207.
It is an arithmetic number, because the mean of its divisors is an integer number (5748019207).
Almost surely, 211496038413 is an apocalyptic number.
It is an amenable number.
11496038413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11496038413 is an equidigital number, since it uses as much as digits as its factorization.
11496038413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 11496038413 in words is "eleven billion, four hundred ninety-six million, thirty-eight thousand, four hundred thirteen".
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