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114984433 is a prime number
BaseRepresentation
bin1101101101010…
…00010111110001
322000100210222201
412312220113301
5213414000213
615224303201
72564231404
oct666502761
9260323881
10114984433
11599a6563
1232611b01
131aa8c035
14113b1d3b
15a1646dd
hex6da85f1

114984433 has 2 divisors, whose sum is σ = 114984434. Its totient is φ = 114984432.

The previous prime is 114984367. The next prime is 114984437. The reversal of 114984433 is 334489411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109998144 + 4986289 = 10488^2 + 2233^2 .

It is a cyclic number.

It is not a de Polignac number, because 114984433 - 225 = 81430001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114984392 and 114984401.

It is not a weakly prime, because it can be changed into another prime (114984437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57492216 + 57492217.

It is an arithmetic number, because the mean of its divisors is an integer number (57492217).

Almost surely, 2114984433 is an apocalyptic number.

It is an amenable number.

114984433 is a deficient number, since it is larger than the sum of its proper divisors (1).

114984433 is an equidigital number, since it uses as much as digits as its factorization.

114984433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 37.

The square root of 114984433 is about 10723.0794550819. The cubic root of 114984433 is about 486.2724696696.

It can be divided in two parts, 11498 and 4433, that added together give a triangular number (15931 = T178).

The spelling of 114984433 in words is "one hundred fourteen million, nine hundred eighty-four thousand, four hundred thirty-three".