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11498713573 is a prime number
BaseRepresentation
bin10101011010110000…
…00111000111100101
31002200100212011122111
422231120013013211
5142022132313243
65141001201021
7554643311164
oct125530070745
932610764574
1011498713573
1149707a6776
12228aa90171
13111334c039
147b120d3db
1547475139d
hex2ad6071e5

11498713573 has 2 divisors, whose sum is σ = 11498713574. Its totient is φ = 11498713572.

The previous prime is 11498713559. The next prime is 11498713579. The reversal of 11498713573 is 37531789411.

11498713573 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10892470689 + 606242884 = 104367^2 + 24622^2 .

It is a cyclic number.

It is not a de Polignac number, because 11498713573 - 213 = 11498705381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11498713579) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5749356786 + 5749356787.

It is an arithmetic number, because the mean of its divisors is an integer number (5749356787).

Almost surely, 211498713573 is an apocalyptic number.

It is an amenable number.

11498713573 is a deficient number, since it is larger than the sum of its proper divisors (1).

11498713573 is an equidigital number, since it uses as much as digits as its factorization.

11498713573 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 635040, while the sum is 49.

The spelling of 11498713573 in words is "eleven billion, four hundred ninety-eight million, seven hundred thirteen thousand, five hundred seventy-three".