Base | Representation |
---|---|
bin | 10000101110111110101… |
… | …111100001110000000001 |
3 | 11001221020102211201202201 |
4 | 100232332233201300001 |
5 | 122320102314214311 |
6 | 2240141020313201 |
7 | 146036664051001 |
oct | 20567657416001 |
9 | 4057212751681 |
10 | 1149956398081 |
11 | 40376a4532a7 |
12 | 166a520a2801 |
13 | 845957bcb3a |
14 | 3d9300c8001 |
15 | 1eda65d19c1 |
hex | 10bbebe1c01 |
1149956398081 has 2 divisors, whose sum is σ = 1149956398082. Its totient is φ = 1149956398080.
The previous prime is 1149956398027. The next prime is 1149956398127. The reversal of 1149956398081 is 1808936599411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1098974822400 + 50981575681 = 1048320^2 + 225791^2 .
It is a cyclic number.
It is not a de Polignac number, because 1149956398081 - 229 = 1149419527169 is a prime.
It is a super-2 number, since 2×11499563980812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1149956398181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574978199040 + 574978199041.
It is an arithmetic number, because the mean of its divisors is an integer number (574978199041).
Almost surely, 21149956398081 is an apocalyptic number.
It is an amenable number.
1149956398081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1149956398081 is an equidigital number, since it uses as much as digits as its factorization.
1149956398081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16796160, while the sum is 64.
The spelling of 1149956398081 in words is "one trillion, one hundred forty-nine billion, nine hundred fifty-six million, three hundred ninety-eight thousand, eighty-one".
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