Base | Representation |
---|---|
bin | 10000101111000001010… |
… | …110000101011010011001 |
3 | 11001221100110222222201221 |
4 | 100233001112011122121 |
5 | 122320200003410212 |
6 | 2240145220212041 |
7 | 146041034140252 |
oct | 20570126053231 |
9 | 4057313888657 |
10 | 1150000060057 |
11 | 403792065182 |
12 | 166a6483a021 |
13 | 845a1869424 |
14 | 3d935c11b29 |
15 | 1edaa358807 |
hex | 10bc1585699 |
1150000060057 has 2 divisors, whose sum is σ = 1150000060058. Its totient is φ = 1150000060056.
The previous prime is 1150000060051. The next prime is 1150000060127. The reversal of 1150000060057 is 7500600000511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 679213332736 + 470786727321 = 824144^2 + 686139^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1150000060057 is a prime.
It is a super-2 number, since 2×11500000600572 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1150000060051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575000030028 + 575000030029.
It is an arithmetic number, because the mean of its divisors is an integer number (575000030029).
Almost surely, 21150000060057 is an apocalyptic number.
It is an amenable number.
1150000060057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150000060057 is an equidigital number, since it uses as much as digits as its factorization.
1150000060057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1050, while the sum is 25.
Adding to 1150000060057 its reverse (7500600000511), we get a palindrome (8650600060568).
The spelling of 1150000060057 in words is "one trillion, one hundred fifty billion, sixty thousand, fifty-seven".
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