115000043325151 has 2 divisors, whose sum is σ = 115000043325152. Its totient is φ = 115000043325150.

The previous prime is 115000043325091. The next prime is 115000043325227. The reversal of 115000043325151 is 151523340000511.

It is a weak prime.

It is an emirp because it is prime and its reverse (151523340000511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115000043325151 - 2¹³ = 115000043316959 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115000043325851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57500021662575 + 57500021662576.

It is an arithmetic number, because the mean of its divisors is an integer number (57500021662576).

Almost surely, 2^{115000043325151} is an apocalyptic number.

115000043325151 is a deficient number, since it is larger than the sum of its proper divisors (1).

115000043325151 is an equidigital number, since it uses as much as digits as its factorization.

115000043325151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 115000043325151 its reverse (151523340000511), we get a palindrome (266523383325662).

The spelling of 115000043325151 in words is "one hundred fifteen trillion, forty-three million, three hundred twenty-five thousand, one hundred fifty-one".