Base | Representation |
---|---|
bin | 100010010001011… |
… | …1100101011010101 |
3 | 2222010221200001101 |
4 | 1010202330223111 |
5 | 4323400341432 |
6 | 310040430101 |
7 | 40332641002 |
oct | 10442745325 |
9 | 2863850041 |
10 | 1150012117 |
11 | 540174141 |
12 | 281178331 |
13 | 154341757 |
14 | aca3a8a9 |
15 | 6ae644e7 |
hex | 448bcad5 |
1150012117 has 2 divisors, whose sum is σ = 1150012118. Its totient is φ = 1150012116.
The previous prime is 1150012099. The next prime is 1150012151. The reversal of 1150012117 is 7112100511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 906371236 + 243640881 = 30106^2 + 15609^2 .
It is a cyclic number.
It is not a de Polignac number, because 1150012117 - 215 = 1149979349 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1150012094 and 1150012103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1150012217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575006058 + 575006059.
It is an arithmetic number, because the mean of its divisors is an integer number (575006059).
Almost surely, 21150012117 is an apocalyptic number.
It is an amenable number.
1150012117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150012117 is an equidigital number, since it uses as much as digits as its factorization.
1150012117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 70, while the sum is 19.
The square root of 1150012117 is about 33911.8285705740. The cubic root of 1150012117 is about 1047.6932328266.
Adding to 1150012117 its reverse (7112100511), we get a palindrome (8262112628).
The spelling of 1150012117 in words is "one billion, one hundred fifty million, twelve thousand, one hundred seventeen".
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