Base | Representation |
---|---|
bin | 10101011010111010… |
… | …11111000010001101 |
3 | 1002200110111201222211 |
4 | 22231131133002031 |
5 | 142023012403003 |
6 | 5141051310421 |
7 | 554661266134 |
oct | 125535370215 |
9 | 32613451884 |
10 | 11500122253 |
11 | 4971579074 |
12 | 228b44b411 |
13 | 1113723289 |
14 | 7b149891b |
15 | 47492d96d |
hex | 2ad75f08d |
11500122253 has 2 divisors, whose sum is σ = 11500122254. Its totient is φ = 11500122252.
The previous prime is 11500122203. The next prime is 11500122269. The reversal of 11500122253 is 35222100511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7782415524 + 3717706729 = 88218^2 + 60973^2 .
It is a cyclic number.
It is not a de Polignac number, because 11500122253 - 29 = 11500121741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11500122203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750061126 + 5750061127.
It is an arithmetic number, because the mean of its divisors is an integer number (5750061127).
Almost surely, 211500122253 is an apocalyptic number.
It is an amenable number.
11500122253 is a deficient number, since it is larger than the sum of its proper divisors (1).
11500122253 is an equidigital number, since it uses as much as digits as its factorization.
11500122253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 600, while the sum is 22.
Adding to 11500122253 its reverse (35222100511), we get a palindrome (46722222764).
The spelling of 11500122253 in words is "eleven billion, five hundred million, one hundred twenty-two thousand, two hundred fifty-three".
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