Search a number
-
+
115003120011407 is a prime number
BaseRepresentation
bin11010001001100001000000…
…000111011100100010001111
3120002012012011011111220120022
4122021201000013130202033
5110033202342210331112
61044331412021012355
733136462344114125
oct3211410007344217
9502165134456508
10115003120011407
1133709605137481
1210a944602540bb
134c22994879104
142058275c0d915
15d46765cd1d72
hex6898401dc88f

115003120011407 has 2 divisors, whose sum is σ = 115003120011408. Its totient is φ = 115003120011406.

The previous prime is 115003120011397. The next prime is 115003120011487. The reversal of 115003120011407 is 704110021300511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115003120011407 - 246 = 44634375833743 is a prime.

It is a super-2 number, since 2×1150031200114072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115003120011487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57501560005703 + 57501560005704.

It is an arithmetic number, because the mean of its divisors is an integer number (57501560005704).

Almost surely, 2115003120011407 is an apocalyptic number.

115003120011407 is a deficient number, since it is larger than the sum of its proper divisors (1).

115003120011407 is an equidigital number, since it uses as much as digits as its factorization.

115003120011407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 26.

Adding to 115003120011407 its reverse (704110021300511), we get a palindrome (819113141311918).

The spelling of 115003120011407 in words is "one hundred fifteen trillion, three billion, one hundred twenty million, eleven thousand, four hundred seven".