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115003120011432 = 2334791796667143
BaseRepresentation
bin11010001001100001000000…
…000111011100100010101000
3120002012012011011111220121020
4122021201000013130202220
5110033202342210331212
61044331412021012440
733136462344114162
oct3211410007344250
9502165134456536
10115003120011432
11337096051374a4
1210a94460254120
134c22994879123
142058275c0d932
15d46765cd1d8c
hex6898401dc8a8

115003120011432 has 16 divisors (see below), whose sum is σ = 287507800028640. Its totient is φ = 38334373337136.

The previous prime is 115003120011407. The next prime is 115003120011487. The reversal of 115003120011432 is 234110021300511.

It is a super-2 number, since 2×1150031200114322 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24), and also a Moran number because the ratio is a prime number: 4791796667143 = 115003120011432 / (1 + 1 + 5 + 0 + 0 + 3 + 1 + 2 + 0 + 0 + 1 + 1 + 4 + 3 + 2).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2395898333548 + ... + 2395898333595.

It is an arithmetic number, because the mean of its divisors is an integer number (17969237501790).

Almost surely, 2115003120011432 is an apocalyptic number.

115003120011432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

115003120011432 is an abundant number, since it is smaller than the sum of its proper divisors (172504680017208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115003120011432 is a wasteful number, since it uses less digits than its factorization.

115003120011432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4791796667152 (or 4791796667148 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 115003120011432 its reverse (234110021300511), we get a palindrome (349113141311943).

The spelling of 115003120011432 in words is "one hundred fifteen trillion, three billion, one hundred twenty million, eleven thousand, four hundred thirty-two".

Divisors: 1 2 3 4 6 8 12 24 4791796667143 9583593334286 14375390001429 19167186668572 28750780002858 38334373337144 57501560005716 115003120011432