Base | Representation |
---|---|
bin | 1010011101011010000000… |
… | …0001010100001111100011 |
3 | 1111201102022112020022020111 |
4 | 2213112200001110033203 |
5 | 3001410114402313021 |
6 | 40243100453152151 |
7 | 2264604312251155 |
oct | 247264001241743 |
9 | 44642275208214 |
10 | 11500312151011 |
11 | 3734289440052 |
12 | 1358a0732b657 |
13 | 655623135568 |
14 | 2ba892012ad5 |
15 | 14e2398eb8e1 |
hex | a75a00543e3 |
11500312151011 has 2 divisors, whose sum is σ = 11500312151012. Its totient is φ = 11500312151010.
The previous prime is 11500312150979. The next prime is 11500312151017. The reversal of 11500312151011 is 11015121300511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11500312151011 - 25 = 11500312150979 is a prime.
It is not a weakly prime, because it can be changed into another prime (11500312151017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750156075505 + 5750156075506.
It is an arithmetic number, because the mean of its divisors is an integer number (5750156075506).
Almost surely, 211500312151011 is an apocalyptic number.
11500312151011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11500312151011 is an equidigital number, since it uses as much as digits as its factorization.
11500312151011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 150, while the sum is 22.
Adding to 11500312151011 its reverse (11015121300511), we get a palindrome (22515433451522).
The spelling of 11500312151011 in words is "eleven trillion, five hundred billion, three hundred twelve million, one hundred fifty-one thousand, eleven".
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