11500441133 has 4 divisors (see below), whose sum is σ = 11511728160. Its totient is φ = 11489154108.

The previous prime is 11500441123. The next prime is 11500441151. The reversal of 11500441133 is 33114400511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33114400511 = 47 ⋅704561713.

It is a cyclic number.

It is not a de Polignac number, because 11500441133 - 2⁸ = 11500440877 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11500441099 and 11500441108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11500441123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5641985 + ... + 5644022.

It is an arithmetic number, because the mean of its divisors is an integer number (2877932040).

Almost surely, 2^11500441133 is an apocalyptic number.

It is an amenable number.

11500441133 is a deficient number, since it is larger than the sum of its proper divisors (11287027).

11500441133 is a wasteful number, since it uses less digits than its factorization.

11500441133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11287026.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 11500441133 its reverse (33114400511), we get a palindrome (44614841644).

The spelling of 11500441133 in words is "eleven billion, five hundred million, four hundred forty-one thousand, one hundred thirty-three".