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115013296903 is a prime number
BaseRepresentation
bin110101100011101010…
…0111010001100000111
3101222212110210211212011
41223013110322030013
53341021401000103
6124500354035051
711211064615261
oct1530724721407
9358773724764
10115013296903
114486000a29a
121a359878a87
13aacc032b8b
1457d0d46b31
152ed22c8d6d
hex1ac753a307

115013296903 has 2 divisors, whose sum is σ = 115013296904. Its totient is φ = 115013296902.

The previous prime is 115013296789. The next prime is 115013296927. The reversal of 115013296903 is 309692310511.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115013296903 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115013296973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57506648451 + 57506648452.

It is an arithmetic number, because the mean of its divisors is an integer number (57506648452).

Almost surely, 2115013296903 is an apocalyptic number.

115013296903 is a deficient number, since it is larger than the sum of its proper divisors (1).

115013296903 is an equidigital number, since it uses as much as digits as its factorization.

115013296903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43740, while the sum is 40.

The spelling of 115013296903 in words is "one hundred fifteen billion, thirteen million, two hundred ninety-six thousand, nine hundred three".