11501705048147 has 2 divisors, whose sum is σ = 11501705048148. Its totient is φ = 11501705048146.

The previous prime is 11501705048089. The next prime is 11501705048191. The reversal of 11501705048147 is 74184050710511.

11501705048147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (11501705048191) can be obtained adding 11501705048147 to its sum of digits (44).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11501705048147 - 2¹⁴ = 11501705031763 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11501705048098 and 11501705048107.

It is not a weakly prime, because it can be changed into another prime (11501705038147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750852524073 + 5750852524074.

It is an arithmetic number, because the mean of its divisors is an integer number (5750852524074).

Almost surely, 2^{11501705048147} is an apocalyptic number.

11501705048147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11501705048147 is an equidigital number, since it uses as much as digits as its factorization.

11501705048147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 156800, while the sum is 44.

Adding to 11501705048147 its reverse (74184050710511), we get a palindrome (85685755758658).

The spelling of 11501705048147 in words is "eleven trillion, five hundred one billion, seven hundred five million, forty-eight thousand, one hundred forty-seven".