1150235114081 has 2 divisors, whose sum is σ = 1150235114082. Its totient is φ = 1150235114080.

The previous prime is 1150235114069. The next prime is 1150235114099. The reversal of 1150235114081 is 1804115320511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1042645210000 + 107589904081 = 1021100^2 + 328009^2 .

It is a cyclic number.

It is not a de Polignac number, because 1150235114081 - 2¹⁰ = 1150235113057 is a prime.

It is a super-2 number, since 2×1150235114081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1150235114011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575117557040 + 575117557041.

It is an arithmetic number, because the mean of its divisors is an integer number (575117557041).

Almost surely, 2^{1150235114081} is an apocalyptic number.

It is an amenable number.

1150235114081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150235114081 is an equidigital number, since it uses as much as digits as its factorization.

1150235114081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 32.

The spelling of 1150235114081 in words is "one trillion, one hundred fifty billion, two hundred thirty-five million, one hundred fourteen thousand, eighty-one".