1150242433 has 2 divisors, whose sum is σ = 1150242434. Its totient is φ = 1150242432.

The previous prime is 1150242419. The next prime is 1150242437. The reversal of 1150242433 is 3342420511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 759112704 + 391129729 = 27552^2 + 19777^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1150242433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1150242398 and 1150242407.

It is not a weakly prime, because it can be changed into another prime (1150242437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575121216 + 575121217.

It is an arithmetic number, because the mean of its divisors is an integer number (575121217).

Almost surely, 2^1150242433 is an apocalyptic number.

It is an amenable number.

1150242433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150242433 is an equidigital number, since it uses as much as digits as its factorization.

1150242433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 1150242433 is about 33915.2242068367. The cubic root of 1150242433 is about 1047.7631695992.

Adding to 1150242433 its reverse (3342420511), we get a palindrome (4492662944).

It can be divided in two parts, 11502 and 42433, that added together give a palindrome (53935).

The spelling of 1150242433 in words is "one billion, one hundred fifty million, two hundred forty-two thousand, four hundred thirty-three".