Base | Representation |
---|---|
bin | 100010010010000… |
… | …0111111000010111 |
3 | 2222011112022121001 |
4 | 1010210013320113 |
5 | 4323440221101 |
6 | 310051204131 |
7 | 40335363031 |
oct | 10444077027 |
9 | 2864468531 |
10 | 1150320151 |
11 | 540364612 |
12 | 2812a6647 |
13 | 15441ba16 |
14 | acabac51 |
15 | 6aec5901 |
hex | 44907e17 |
1150320151 has 2 divisors, whose sum is σ = 1150320152. Its totient is φ = 1150320150.
The previous prime is 1150320107. The next prime is 1150320167. The reversal of 1150320151 is 1510230511.
It is a strong prime.
It is an emirp because it is prime and its reverse (1510230511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1150320151 - 225 = 1116765719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1150320251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575160075 + 575160076.
It is an arithmetic number, because the mean of its divisors is an integer number (575160076).
Almost surely, 21150320151 is an apocalyptic number.
1150320151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150320151 is an equidigital number, since it uses as much as digits as its factorization.
1150320151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 19.
The square root of 1150320151 is about 33916.3699561141. The cubic root of 1150320151 is about 1047.7867670084.
Adding to 1150320151 its reverse (1510230511), we get a palindrome (2660550662).
The spelling of 1150320151 in words is "one billion, one hundred fifty million, three hundred twenty thousand, one hundred fifty-one".
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