115032224130040 has 128 divisors (see below), whose sum is σ = 296247671654400. Its totient is φ = 39379564477440.

The previous prime is 115032224130001. The next prime is 115032224130041. The reversal of 115032224130040 is 40031422230511.

It is a Harshad number since it is a multiple of its sum of digits (28).

It is a junction number, because it is equal to n+sod(n) for n = 115032224129990 and 115032224130008.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115032224130041) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1718635375 + ... + 1718702305.

It is an arithmetic number, because the mean of its divisors is an integer number (2314434934800).

Almost surely, 2^{115032224130040} is an apocalyptic number.

115032224130040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 115032224130040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (148123835827200).

115032224130040 is an abundant number, since it is smaller than the sum of its proper divisors (181215447524360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115032224130040 is a wasteful number, since it uses less digits than its factorization.

115032224130040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76205 (or 76201 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 115032224130040 its reverse (40031422230511), we get a palindrome (155063646360551).

The spelling of 115032224130040 in words is "one hundred fifteen trillion, thirty-two billion, two hundred twenty-four million, one hundred thirty thousand, forty".