115040131 has 2 divisors, whose sum is σ = 115040132. Its totient is φ = 115040130.

The previous prime is 115040119. The next prime is 115040143. The reversal of 115040131 is 131040511.

It is a balanced prime because it is at equal distance from previous prime (115040119) and next prime (115040143).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115040131 is a prime.

It is a super-3 number, since 3×115040131³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (115040171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57520065 + 57520066.

It is an arithmetic number, because the mean of its divisors is an integer number (57520066).

Almost surely, 2^115040131 is an apocalyptic number.

115040131 is a deficient number, since it is larger than the sum of its proper divisors (1).

115040131 is an equidigital number, since it uses as much as digits as its factorization.

115040131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 115040131 is about 10725.6762490763. The cubic root of 115040131 is about 486.3509731426.

Adding to 115040131 its reverse (131040511), we get a palindrome (246080642).

The spelling of 115040131 in words is "one hundred fifteen million, forty thousand, one hundred thirty-one".