Base | Representation |
---|---|
bin | 110101100100100010… |
… | …0011100101100110111 |
3 | 101222221111211100200211 |
4 | 1223021010130230313 |
5 | 3341101342124442 |
6 | 124503320450251 |
7 | 11211601265212 |
oct | 1531104345467 |
9 | 358844740624 |
10 | 115042536247 |
11 | 44875570241 |
12 | 1a367619987 |
13 | ab050cc872 |
14 | 57d4b98779 |
15 | 2ed4b52617 |
hex | 1ac911cb37 |
115042536247 has 2 divisors, whose sum is σ = 115042536248. Its totient is φ = 115042536246.
The previous prime is 115042536233. The next prime is 115042536277. The reversal of 115042536247 is 742635240511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115042536247 is a prime.
It is a super-2 number, since 2×1150425362472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115042536277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57521268123 + 57521268124.
It is an arithmetic number, because the mean of its divisors is an integer number (57521268124).
Almost surely, 2115042536247 is an apocalyptic number.
115042536247 is a deficient number, since it is larger than the sum of its proper divisors (1).
115042536247 is an equidigital number, since it uses as much as digits as its factorization.
115042536247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 40.
Adding to 115042536247 its reverse (742635240511), we get a palindrome (857677776758).
The spelling of 115042536247 in words is "one hundred fifteen billion, forty-two million, five hundred thirty-six thousand, two hundred forty-seven".
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