Base | Representation |
---|---|
bin | 1010011101101001110000… |
… | …1010011110001001111101 |
3 | 1111201211020100012200201221 |
4 | 2213122130022132021331 |
5 | 3001442300324044331 |
6 | 40245040330233341 |
7 | 2265114166664632 |
oct | 247323412361175 |
9 | 44654210180657 |
10 | 11504542409341 |
11 | 373605a2a3813 |
12 | 13597a7b85851 |
13 | 655b486769b7 |
14 | 2bab73b84189 |
15 | 14e3d5ea6711 |
hex | a769c29e27d |
11504542409341 has 2 divisors, whose sum is σ = 11504542409342. Its totient is φ = 11504542409340.
The previous prime is 11504542409323. The next prime is 11504542409407. The reversal of 11504542409341 is 14390424540511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6170151672441 + 5334390736900 = 2483979^2 + 2309630^2 .
It is a cyclic number.
It is not a de Polignac number, because 11504542409341 - 217 = 11504542278269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11504542409441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5752271204670 + 5752271204671.
It is an arithmetic number, because the mean of its divisors is an integer number (5752271204671).
Almost surely, 211504542409341 is an apocalyptic number.
It is an amenable number.
11504542409341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11504542409341 is an equidigital number, since it uses as much as digits as its factorization.
11504542409341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 43.
Adding to 11504542409341 its reverse (14390424540511), we get a palindrome (25894966949852).
The spelling of 11504542409341 in words is "eleven trillion, five hundred four billion, five hundred forty-two million, four hundred nine thousand, three hundred forty-one".
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