Base | Representation |
---|---|
bin | 10000101111100110010… |
… | …100001011001101000001 |
3 | 11001222221201010021121002 |
4 | 100233212110023031001 |
5 | 122322432300111411 |
6 | 2240330534341345 |
7 | 146062305214106 |
oct | 20574624131501 |
9 | 4058851107532 |
10 | 1150620316481 |
11 | 403a80198a99 |
12 | 166bb84ba855 |
13 | 8467020806c |
14 | 3d99434caad |
15 | 1ede4a2833b |
hex | 10be650b341 |
1150620316481 has 2 divisors, whose sum is σ = 1150620316482. Its totient is φ = 1150620316480.
The previous prime is 1150620316477. The next prime is 1150620316583. The reversal of 1150620316481 is 1846130260511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 633004819456 + 517615497025 = 795616^2 + 719455^2 .
It is a cyclic number.
It is not a de Polignac number, because 1150620316481 - 22 = 1150620316477 is a prime.
It is a super-2 number, since 2×11506203164812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1150620316411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575310158240 + 575310158241.
It is an arithmetic number, because the mean of its divisors is an integer number (575310158241).
Almost surely, 21150620316481 is an apocalyptic number.
It is an amenable number.
1150620316481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150620316481 is an equidigital number, since it uses as much as digits as its factorization.
1150620316481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 38.
Adding to 1150620316481 its reverse (1846130260511), we get a palindrome (2996750576992).
The spelling of 1150620316481 in words is "one trillion, one hundred fifty billion, six hundred twenty million, three hundred sixteen thousand, four hundred eighty-one".
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