Base | Representation |
---|---|
bin | 10101011011101110… |
… | …10100111010101001 |
3 | 1002200221020220120211 |
4 | 22231313110322221 |
5 | 142031231142203 |
6 | 5141452421121 |
7 | 555103002235 |
oct | 125567247251 |
9 | 32627226524 |
10 | 11506896553 |
11 | 4975385769 |
12 | 22917777a1 |
13 | 1114c55839 |
14 | 7b233d5c5 |
15 | 47531ac6d |
hex | 2addd4ea9 |
11506896553 has 2 divisors, whose sum is σ = 11506896554. Its totient is φ = 11506896552.
The previous prime is 11506896551. The next prime is 11506896581. The reversal of 11506896553 is 35569860511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11125397529 + 381499024 = 105477^2 + 19532^2 .
It is a cyclic number.
It is not a de Polignac number, because 11506896553 - 21 = 11506896551 is a prime.
Together with 11506896551, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11506896497 and 11506896506.
It is not a weakly prime, because it can be changed into another prime (11506896551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5753448276 + 5753448277.
It is an arithmetic number, because the mean of its divisors is an integer number (5753448277).
Almost surely, 211506896553 is an apocalyptic number.
It is an amenable number.
11506896553 is a deficient number, since it is larger than the sum of its proper divisors (1).
11506896553 is an equidigital number, since it uses as much as digits as its factorization.
11506896553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 49.
The spelling of 11506896553 in words is "eleven billion, five hundred six million, eight hundred ninety-six thousand, five hundred fifty-three".
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