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1150753443857 is a prime number
BaseRepresentation
bin10000101111101110010…
…000000001000000010001
311002000021222121212000122
4100233232100001000101
5122323220340200412
62240352052000025
7146065512611423
oct20575620010021
94060258555018
101150753443857
11404039356616
12167035000015
138469197a164
143d9a7cc4813
151ee01573572
hex10bee401011

1150753443857 has 2 divisors, whose sum is σ = 1150753443858. Its totient is φ = 1150753443856.

The previous prime is 1150753443811. The next prime is 1150753443883. The reversal of 1150753443857 is 7583443570511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 836655966721 + 314097477136 = 914689^2 + 560444^2 .

It is a cyclic number.

It is not a de Polignac number, because 1150753443857 - 212 = 1150753439761 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1150753443799 and 1150753443808.

It is not a weakly prime, because it can be changed into another prime (1150753442857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575376721928 + 575376721929.

It is an arithmetic number, because the mean of its divisors is an integer number (575376721929).

Almost surely, 21150753443857 is an apocalyptic number.

It is an amenable number.

1150753443857 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150753443857 is an equidigital number, since it uses as much as digits as its factorization.

1150753443857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7056000, while the sum is 53.

The spelling of 1150753443857 in words is "one trillion, one hundred fifty billion, seven hundred fifty-three million, four hundred forty-three thousand, eight hundred fifty-seven".