Base | Representation |
---|---|
bin | 110101100110010000… |
… | …0000010010111001001 |
3 | 102000002112010220101012 |
4 | 1223030200002113021 |
5 | 3341211111200131 |
6 | 124513134333305 |
7 | 11213200464533 |
oct | 1531440022711 |
9 | 360075126335 |
10 | 115100100041 |
11 | 448a5007823 |
12 | 1a38295a235 |
13 | ab14005994 |
14 | 57dc6a0853 |
15 | 2ed9c2352b |
hex | 1acc8025c9 |
115100100041 has 2 divisors, whose sum is σ = 115100100042. Its totient is φ = 115100100040.
The previous prime is 115100100001. The next prime is 115100100121. The reversal of 115100100041 is 140001001511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79140942400 + 35959157641 = 281320^2 + 189629^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115100100041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115100099989 and 115100100025.
It is not a weakly prime, because it can be changed into another prime (115100100001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57550050020 + 57550050021.
It is an arithmetic number, because the mean of its divisors is an integer number (57550050021).
Almost surely, 2115100100041 is an apocalyptic number.
It is an amenable number.
115100100041 is a deficient number, since it is larger than the sum of its proper divisors (1).
115100100041 is an equidigital number, since it uses as much as digits as its factorization.
115100100041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 115100100041 its reverse (140001001511), we get a palindrome (255101101552).
The spelling of 115100100041 in words is "one hundred fifteen billion, one hundred million, one hundred thousand, forty-one".
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