Base | Representation |
---|---|
bin | 110101100110010000… |
… | …0000010011000011001 |
3 | 102000002112010220111011 |
4 | 1223030200002120121 |
5 | 3341211111200441 |
6 | 124513134333521 |
7 | 11213200465006 |
oct | 1531440023031 |
9 | 360075126434 |
10 | 115100100121 |
11 | 448a5007896 |
12 | 1a38295a2a1 |
13 | ab14005a26 |
14 | 57dc6a08ad |
15 | 2ed9c23581 |
hex | 1acc802619 |
115100100121 has 2 divisors, whose sum is σ = 115100100122. Its totient is φ = 115100100120.
The previous prime is 115100100041. The next prime is 115100100221. The reversal of 115100100121 is 121001001511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72060033600 + 43040066521 = 268440^2 + 207461^2 .
It is a cyclic number.
It is not a de Polignac number, because 115100100121 - 233 = 106510165529 is a prime.
It is not a weakly prime, because it can be changed into another prime (115100100221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57550050060 + 57550050061.
It is an arithmetic number, because the mean of its divisors is an integer number (57550050061).
Almost surely, 2115100100121 is an apocalyptic number.
It is an amenable number.
115100100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
115100100121 is an equidigital number, since it uses as much as digits as its factorization.
115100100121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10, while the sum is 13.
Adding to 115100100121 its reverse (121001001511), we get a palindrome (236101101632).
The spelling of 115100100121 in words is "one hundred fifteen billion, one hundred million, one hundred thousand, one hundred twenty-one".
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