Base | Representation |
---|---|
bin | 10000101111111101101… |
… | …010110101000100011111 |
3 | 11002000222000101112012202 |
4 | 100233331222311010133 |
5 | 122324233101143403 |
6 | 2240433452322115 |
7 | 146105103454562 |
oct | 20577552650437 |
9 | 4060860345182 |
10 | 1151012131103 |
11 | 40416138312a |
12 | 1670a777333b |
13 | 84703441a33 |
14 | 3d9d03c24d9 |
15 | 1ee19121688 |
hex | 10bfdab511f |
1151012131103 has 2 divisors, whose sum is σ = 1151012131104. Its totient is φ = 1151012131102.
The previous prime is 1151012131043. The next prime is 1151012131109. The reversal of 1151012131103 is 3011312101511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1151012131103 - 212 = 1151012127007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1151012131109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575506065551 + 575506065552.
It is an arithmetic number, because the mean of its divisors is an integer number (575506065552).
Almost surely, 21151012131103 is an apocalyptic number.
1151012131103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1151012131103 is an equidigital number, since it uses as much as digits as its factorization.
1151012131103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 1151012131103 its reverse (3011312101511), we get a palindrome (4162324232614).
The spelling of 1151012131103 in words is "one trillion, one hundred fifty-one billion, twelve million, one hundred thirty-one thousand, one hundred three".
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