115111141125 has 16 divisors (see below), whose sum is σ = 191544939456. Its totient is φ = 61392608400.

The previous prime is 115111141009. The next prime is 115111141133. The reversal of 115111141125 is 521141111511.

It is not a de Polignac number, because 115111141125 - 2¹⁰ = 115111140101 is a prime.

It is a super-3 number, since 3×115111141125³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 115111141095 and 115111141104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153481147 + ... + 153481896.

It is an arithmetic number, because the mean of its divisors is an integer number (11971558716).

Almost surely, 2^115111141125 is an apocalyptic number.

115111141125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

115111141125 is a deficient number, since it is larger than the sum of its proper divisors (76433798331).

115111141125 is an equidigital number, since it uses as much as digits as its factorization.

115111141125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 306963061 (or 306963051 counting only the distinct ones).

The product of its digits is 200, while the sum is 24.

Adding to 115111141125 its reverse (521141111511), we get a palindrome (636252252636).

The spelling of 115111141125 in words is "one hundred fifteen billion, one hundred eleven million, one hundred forty-one thousand, one hundred twenty-five".