11512031100103 has 2 divisors, whose sum is σ = 11512031100104. Its totient is φ = 11512031100102.

The previous prime is 11512031100001. The next prime is 11512031100133. The reversal of 11512031100103 is 30100113021511.

11512031100103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11512031100103 is a prime.

It is a super-2 number, since 2×11512031100103² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11512031100133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756015550051 + 5756015550052.

It is an arithmetic number, because the mean of its divisors is an integer number (5756015550052).

Almost surely, 2^{11512031100103} is an apocalyptic number.

11512031100103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11512031100103 is an equidigital number, since it uses as much as digits as its factorization.

11512031100103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 11512031100103 its reverse (30100113021511), we get a palindrome (41612144121614).

The spelling of 11512031100103 in words is "eleven trillion, five hundred twelve billion, thirty-one million, one hundred thousand, one hundred three".