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11512031100413 is a prime number
BaseRepresentation
bin1010011110000101101010…
…0001100011110111111101
31111202112120020111121122112
42213201122201203313331
53002103114430203123
640252315403023405
72265500601550334
oct247413241436775
944675506447575
1011512031100413
1137392524901a8
12135b137b0ab65
1365676cca544c
142bb284590d1b
1514e6c3652d78
hexa785a863dfd

11512031100413 has 2 divisors, whose sum is σ = 11512031100414. Its totient is φ = 11512031100412.

The previous prime is 11512031100329. The next prime is 11512031100461. The reversal of 11512031100413 is 31400113021511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7928267855524 + 3583763244889 = 2815718^2 + 1893083^2 .

It is a cyclic number.

It is not a de Polignac number, because 11512031100413 - 212 = 11512031096317 is a prime.

It is a super-2 number, since 2×115120311004132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11512031103413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756015550206 + 5756015550207.

It is an arithmetic number, because the mean of its divisors is an integer number (5756015550207).

Almost surely, 211512031100413 is an apocalyptic number.

It is an amenable number.

11512031100413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11512031100413 is an equidigital number, since it uses as much as digits as its factorization.

11512031100413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 11512031100413 its reverse (31400113021511), we get a palindrome (42912144121924).

The spelling of 11512031100413 in words is "eleven trillion, five hundred twelve billion, thirty-one million, one hundred thousand, four hundred thirteen".