115121343431 has 2 divisors, whose sum is σ = 115121343432. Its totient is φ = 115121343430.

The previous prime is 115121343419. The next prime is 115121343481. The reversal of 115121343431 is 134343121511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115121343431 - 2⁶ = 115121343367 is a prime.

It is a super-2 number, since 2×115121343431² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115121343394 and 115121343403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115121343481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57560671715 + 57560671716.

It is an arithmetic number, because the mean of its divisors is an integer number (57560671716).

Almost surely, 2^115121343431 is an apocalyptic number.

115121343431 is a deficient number, since it is larger than the sum of its proper divisors (1).

115121343431 is an equidigital number, since it uses as much as digits as its factorization.

115121343431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4320, while the sum is 29.

Adding to 115121343431 its reverse (134343121511), we get a palindrome (249464464942).

The spelling of 115121343431 in words is "one hundred fifteen billion, one hundred twenty-one million, three hundred forty-three thousand, four hundred thirty-one".