Base | Representation |
---|---|
bin | 1010011110000110110100… |
… | …0101010100100111101100 |
3 | 1111202120100221101120120102 |
4 | 2213201231011110213230 |
5 | 3002104234132340004 |
6 | 40252410324410232 |
7 | 2265511402241663 |
oct | 247415505244754 |
9 | 44676327346512 |
10 | 11512342465004 |
11 | 37393a2217007 |
12 | 135b204246978 |
13 | 6567bc651c54 |
14 | 2bb2b3a81dda |
15 | 14e6e0b5911e |
hex | a786d1549ec |
11512342465004 has 24 divisors (see below), whose sum is σ = 21209402079600. Its totient is φ = 5452583454720.
The previous prime is 11512342464967. The next prime is 11512342465009. The reversal of 11512342465004 is 40056424321511.
11512342465004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (38).
It is not an unprimeable number, because it can be changed into a prime (11512342465009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8108369 + ... + 9421800.
It is an arithmetic number, because the mean of its divisors is an integer number (883725086650).
Almost surely, 211512342465004 is an apocalyptic number.
It is an amenable number.
11512342465004 is a deficient number, since it is larger than the sum of its proper divisors (9697059614596).
11512342465004 is a wasteful number, since it uses less digits than its factorization.
11512342465004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17538833 (or 17538831 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 11512342465004 its reverse (40056424321511), we get a palindrome (51568766786515).
The spelling of 11512342465004 in words is "eleven trillion, five hundred twelve billion, three hundred forty-two million, four hundred sixty-five thousand, four".
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