Base | Representation |
---|---|
bin | 1010011110000110110100… |
… | …1100000000001001000010 |
3 | 1111202120101001200112122221 |
4 | 2213201231030000021002 |
5 | 3002104240104404010 |
6 | 40252410430121254 |
7 | 2265511423154212 |
oct | 247415514001102 |
9 | 44676331615587 |
10 | 11512344216130 |
11 | 37393a320271a |
12 | 135b20495022a |
13 | 6567bcb16014 |
14 | 2bb2b3dba242 |
15 | 14e6e0da2dda |
hex | a786d300242 |
11512344216130 has 8 divisors (see below), whose sum is σ = 20722219589052. Its totient is φ = 4604937686448.
The previous prime is 11512344216083. The next prime is 11512344216169. The reversal of 11512344216130 is 3161244321511.
It can be written as a sum of positive squares in 2 ways, for example, as 10694620089169 + 817724126961 = 3270263^2 + 904281^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×115123442161303 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575617210797 + ... + 575617210816.
Almost surely, 211512344216130 is an apocalyptic number.
11512344216130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11512344216130 is a deficient number, since it is larger than the sum of its proper divisors (9209875372922).
11512344216130 is a wasteful number, since it uses less digits than its factorization.
11512344216130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1151234421620.
The product of its (nonzero) digits is 17280, while the sum is 34.
Adding to 11512344216130 its reverse (3161244321511), we get a palindrome (14673588537641).
The spelling of 11512344216130 in words is "eleven trillion, five hundred twelve billion, three hundred forty-four million, two hundred sixteen thousand, one hundred thirty".
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