Base | Representation |
---|---|
bin | 11010001011010010101101… |
… | …010000111111011011001101 |
3 | 120002121212021211221220202210 |
4 | 122023102231100333123031 |
5 | 110042202412320030240 |
6 | 1044503442543541033 |
7 | 33151344014425362 |
oct | 3213225520773315 |
9 | 502555254856683 |
10 | 115125210314445 |
11 | 33756366a07171 |
12 | 10ab4053bba779 |
13 | 4c31350b37686 |
14 | 20601389da469 |
15 | d49a0e536780 |
hex | 68b4ad43f6cd |
115125210314445 has 64 divisors (see below), whose sum is σ = 196285899184128. Its totient is φ = 57493963296000.
The previous prime is 115125210314423. The next prime is 115125210314489. The reversal of 115125210314445 is 544413012521511.
It is not a de Polignac number, because 115125210314445 - 235 = 115090850576077 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8522611 + ... + 17403600.
It is an arithmetic number, because the mean of its divisors is an integer number (3066967174752).
Almost surely, 2115125210314445 is an apocalyptic number.
115125210314445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
115125210314445 is a deficient number, since it is larger than the sum of its proper divisors (81160688869683).
115125210314445 is a wasteful number, since it uses less digits than its factorization.
115125210314445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25926514.
The product of its (nonzero) digits is 96000, while the sum is 39.
Adding to 115125210314445 its reverse (544413012521511), we get a palindrome (659538222835956).
The spelling of 115125210314445 in words is "one hundred fifteen trillion, one hundred twenty-five billion, two hundred ten million, three hundred fourteen thousand, four hundred forty-five".
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