Base | Representation |
---|---|
bin | 1010011110000111100010… |
… | …0011111111011111111111 |
3 | 1111202120212100210010110121 |
4 | 2213201320203333133333 |
5 | 3002110132433214320 |
6 | 40252441404315411 |
7 | 2265516231232630 |
oct | 247417043773777 |
9 | 44676770703417 |
10 | 11512535054335 |
11 | 37394909a8247 |
12 | 135b258842b67 |
13 | 656820513133 |
14 | 2bb2d1495887 |
15 | 14e7029ec8aa |
hex | a78788ff7ff |
11512535054335 has 32 divisors (see below), whose sum is σ = 15877112942592. Its totient is φ = 7850170849920.
The previous prime is 11512535054299. The next prime is 11512535054407. The reversal of 11512535054335 is 53345053521511.
It is not a de Polignac number, because 11512535054335 - 29 = 11512535053823 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11512535054291 and 11512535054300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4004490 + ... + 6249880.
It is an arithmetic number, because the mean of its divisors is an integer number (496159779456).
Almost surely, 211512535054335 is an apocalyptic number.
11512535054335 is a deficient number, since it is larger than the sum of its proper divisors (4364577888257).
11512535054335 is a wasteful number, since it uses less digits than its factorization.
11512535054335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2246223.
The product of its (nonzero) digits is 675000, while the sum is 43.
Adding to 11512535054335 its reverse (53345053521511), we get a palindrome (64857588575846).
The spelling of 11512535054335 in words is "eleven trillion, five hundred twelve billion, five hundred thirty-five million, fifty-four thousand, three hundred thirty-five".
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