Base | Representation |
---|---|
bin | 10101011100011011… |
… | …00111011000001011 |
3 | 1002201100020202101022 |
4 | 22232031213120023 |
5 | 142034230124324 |
6 | 5142221543055 |
7 | 555203445503 |
oct | 125615473013 |
9 | 32640222338 |
10 | 11512739339 |
11 | 4978706512 |
12 | 2293714a8b |
13 | 11162200ca |
14 | 7b3020a03 |
15 | 475ac205e |
hex | 2ae36760b |
11512739339 has 2 divisors, whose sum is σ = 11512739340. Its totient is φ = 11512739338.
The previous prime is 11512739333. The next prime is 11512739383. The reversal of 11512739339 is 93393721511.
It is an a-pointer prime, because the next prime (11512739383) can be obtained adding 11512739339 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11512739339 - 24 = 11512739323 is a prime.
It is a super-4 number, since 4×115127393394 (a number of 41 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11512739339.
It is not a weakly prime, because it can be changed into another prime (11512739333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756369669 + 5756369670.
It is an arithmetic number, because the mean of its divisors is an integer number (5756369670).
Almost surely, 211512739339 is an apocalyptic number.
11512739339 is a deficient number, since it is larger than the sum of its proper divisors (1).
11512739339 is an equidigital number, since it uses as much as digits as its factorization.
11512739339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 153090, while the sum is 44.
The spelling of 11512739339 in words is "eleven billion, five hundred twelve million, seven hundred thirty-nine thousand, three hundred thirty-nine".
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