Base | Representation |
---|---|
bin | 110101100111001001… |
… | …0001001001010111111 |
3 | 102000011121102121100112 |
4 | 1223032102021022333 |
5 | 3341241240343401 |
6 | 124520123420235 |
7 | 11214012646454 |
oct | 1531622111277 |
9 | 360147377315 |
10 | 115130012351 |
11 | 4490a988342 |
12 | 1a39098467b |
13 | ab1a279a83 |
14 | 580264982b |
15 | 2edc6813bb |
hex | 1ace4892bf |
115130012351 has 2 divisors, whose sum is σ = 115130012352. Its totient is φ = 115130012350.
The previous prime is 115130012341. The next prime is 115130012381. The reversal of 115130012351 is 153210031511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115130012351 - 26 = 115130012287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115130012341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565006175 + 57565006176.
It is an arithmetic number, because the mean of its divisors is an integer number (57565006176).
Almost surely, 2115130012351 is an apocalyptic number.
115130012351 is a deficient number, since it is larger than the sum of its proper divisors (1).
115130012351 is an equidigital number, since it uses as much as digits as its factorization.
115130012351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 115130012351 its reverse (153210031511), we get a palindrome (268340043862).
The spelling of 115130012351 in words is "one hundred fifteen billion, one hundred thirty million, twelve thousand, three hundred fifty-one".
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