Base | Representation |
---|---|
bin | 110101100111001001… |
… | …0010000000001010101 |
3 | 102000011121111000211120 |
4 | 1223032102100001111 |
5 | 3341241242243110 |
6 | 124520124154153 |
7 | 11214013124322 |
oct | 1531622200125 |
9 | 360147430746 |
10 | 115130040405 |
11 | 4490a9a7426 |
12 | 1a390998959 |
13 | ab1a289783 |
14 | 5802655b49 |
15 | 2edc689870 |
hex | 1ace490055 |
115130040405 has 8 divisors (see below), whose sum is σ = 184208064672. Its totient is φ = 61402688208.
The previous prime is 115130040391. The next prime is 115130040407. The reversal of 115130040405 is 504040031511.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 115130040405 - 26 = 115130040341 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115130040407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3837667999 + ... + 3837668028.
It is an arithmetic number, because the mean of its divisors is an integer number (23026008084).
Almost surely, 2115130040405 is an apocalyptic number.
115130040405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
115130040405 is a deficient number, since it is larger than the sum of its proper divisors (69078024267).
115130040405 is an equidigital number, since it uses as much as digits as its factorization.
115130040405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7675336035.
The product of its (nonzero) digits is 1200, while the sum is 24.
Adding to 115130040405 its reverse (504040031511), we get a palindrome (619170071916).
The spelling of 115130040405 in words is "one hundred fifteen billion, one hundred thirty million, forty thousand, four hundred five".
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